st(1) implies 1/x - 1/y = 1/y - 1/x <> (y-x)/xy=(x-y)/xy OR y-x=x-y, which is x=y. Any number equal to itself will return 0 if it's subtracted from itself, hence true for all math operations (+,-,*,/) Sufficient;
st(2)implies x/y=y/x OR x^2=y^2, practically means |x|=|y|, hence true only for all math operations except for '-'.
2 and -2, 2-(-2)=!-2-2, 4=!-4 Not Sufficient
shankar.ashwin wrote:Not sure if its tough..
Statement 1:
x @ y = 1/x - 1/y
y @ x = 1/y - 1/x
st(1) implies 1/x - 1/y = 1/y - 1/x <> (y-x)/xy=(x-y)/xy OR y-x=x-y, which is x=y. Any number equal to itself will return 0 if it's subtracted from itself, hence true for all math operations (+,-,*,/) Sufficient;
whereas st(2)implies x/y=y/x OR x^2=y^2, practically means |x|=|y|, hence true only for all math operations except for '-'.
2 and -2, 2-(-2)=!-2-2, 4=!-4 Not Sufficient
1/x - 1/y does not equal 1/y - 1/x for all values of 'x' and 'y' - Sufficient.
Statement 2
Similarly,
x/y does not equal y/x for all 'x' and 'y' - Sufficient
So we could answer 'NO' using both statements alone