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by beat_gmat_09 » Sat Dec 04, 2010 9:13 pm
Question asks how many 3 digit numbers can be formed without repetition.
10 integers 0-9
0 cannot be at hundreds place so 1st place 9
0 can be at tens place, total 10, reject 1 from 1st place = 9
0 can be at tens place, total 10, reject 2 from 1st and 2nd = 8
Total ways = 9*9*8 = 648
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