From stat1: a < 0,parul9 wrote:If a and b are integers, and |a| > |b|, is a · |b| < a - b?
(1) a < 0
(2) ab 0
OA : [spoiler]E Can someone please explain??[/spoiler]
The second statement is ab >= 0. I will edit the main post too!n@resh wrote:From stat1: a < 0,parul9 wrote:If a and b are integers, and |a| > |b|, is a · |b| < a - b?
(1) a < 0
(2) ab 0
OA : [spoiler]E Can someone please explain??[/spoiler]
plug-in numbers: a = -1, b = 0 ; 0 < -1 ( FALSE)
a = -2, b = 1 ; -2 < -3 (FALSE)
a = -2, b = -1 ; -2 < -1 ( TRUE)
clearly, not sufficient.
From stat2: ab 0; it seems expression missing it's relation sign!
well, if we consider <, > then obviously it's not sufficient!
but if we have ab = 0; to satisfy |a| > |b|, then a must be non-zero (but it can be < 0 or >0), so b should be 0!
e.g: a = -2, b = 0; 0 < -2 ( FALSE)
a = 2, b = 0; 0 < 2 ( TRUE)
Hence, it's not sufficient!
NOTE: if i consider, ab = 0 and a < 0 ; then the statement can be solved by using these both statements!
However, as 2nd statement isn't clear then i'll go for not sufficient. E!
Naresh has explained the statement 1...Coming to Statement 2 following the same procedureparul9 wrote:The second statement is ab >= 0. I will edit the main post too!n@resh wrote:From stat1: a < 0,parul9 wrote:If a and b are integers, and |a| > |b|, is a · |b| < a - b?
(1) a < 0
(2) ab 0
OA : [spoiler]E Can someone please explain??[/spoiler]
plug-in numbers: a = -1, b = 0 ; 0 < -1 ( FALSE)
a = -2, b = 1 ; -2 < -3 (FALSE)
a = -2, b = -1 ; -2 < -1 ( TRUE)
clearly, not sufficient.
From stat2: ab 0; it seems expression missing it's relation sign!
well, if we consider <, > then obviously it's not sufficient!
but if we have ab = 0; to satisfy |a| > |b|, then a must be non-zero (but it can be < 0 or >0), so b should be 0!
e.g: a = -2, b = 0; 0 < -2 ( FALSE)
a = 2, b = 0; 0 < 2 ( TRUE)
Hence, it's not sufficient!
NOTE: if i consider, ab = 0 and a < 0 ; then the statement can be solved by using these both statements!
However, as 2nd statement isn't clear then i'll go for not sufficient. E!
...if i am wrong CORRECT ME...ThanksAnswer will be still: E! nevertheless, a can't be zero as per |a| > |b|!nandy1984 wrote:Naresh has explained the statement 1...Coming to Statement 2 following the same procedureparul9 wrote:The second statement is ab >= 0. I will edit the main post too!n@resh wrote:From stat1: a < 0,parul9 wrote:If a and b are integers, and |a| > |b|, is a · |b| < a - b?
(1) a < 0
(2) ab 0
OA : [spoiler]E Can someone please explain??[/spoiler]
plug-in numbers: a = -1, b = 0 ; 0 < -1 ( FALSE)
a = -2, b = 1 ; -2 < -3 (FALSE)
a = -2, b = -1 ; -2 < -1 ( TRUE)
clearly, not sufficient.
From stat2: ab 0; it seems expression missing it's relation sign!
well, if we consider <, > then obviously it's not sufficient!
but if we have ab = 0; to satisfy |a| > |b|, then a must be non-zero (but it can be < 0 or >0), so b should be 0!
e.g: a = -2, b = 0; 0 < -2 ( FALSE)
a = 2, b = 0; 0 < 2 ( TRUE)
Hence, it's not sufficient!
NOTE: if i consider, ab = 0 and a < 0 ; then the statement can be solved by using these both statements!
However, as 2nd statement isn't clear then i'll go for not sufficient. E!
Statement 2 : ab>= 0
There are several conditions like
i) a>0,b>0,ab>0
ii) a<0,b<0,ab>0
iii) a>0,b=0,ab=0
iv) a<0,b=0,ab=0
v) a=0,b<0,ab=0 ---> a*|b|=0 ---> a-b>0 ---> b>0 correct
v)a=0, b>0, ab=0 ---> a*|b|=0 ---> -b>0 which is wrongNo need to solve all the combinations above just the last two combinations have two different results so we can say its INSUFFICIENT.
Combining Statement 1) and 2) we get combinations
(ii)a<0,b<0,ab>0 ----> a*|b|<0 ---> a-b either positive or negative depending on values of "a" and "b" if a=-2,b=-3 then a-b> a*|b| correct...1>-6 ; if a=-3,b=-2 then a-b =-1, a*|b| = -3*2=-6 -1>-6 correct.
(iv)a<0,b=0,ab=0 ----> a=-3 ---> -3>0 wrong...
so from the two combinations we get different answers so its INSUFFICIENT...Ans:E
If anyone can explain this in a more simplistic way you are welcome. I tried my best
HELLO nARESH THIS IS A WONDERFUL POINT I HAVE NOT THOUGHT ABOUT THAT....a can't be zero as per |a| > |b|!...tHANK YOU....n@resh wrote:Answer will be still: E! nevertheless, a can't be zero as per |a| > |b|!nandy1984 wrote:Naresh has explained the statement 1...Coming to Statement 2 following the same procedureparul9 wrote:The second statement is ab >= 0. I will edit the main post too!n@resh wrote:From stat1: a < 0,parul9 wrote:If a and b are integers, and |a| > |b|, is a · |b| < a - b?
(1) a < 0
(2) ab 0
OA : [spoiler]E Can someone please explain??[/spoiler]
plug-in numbers: a = -1, b = 0 ; 0 < -1 ( FALSE)
a = -2, b = 1 ; -2 < -3 (FALSE)
a = -2, b = -1 ; -2 < -1 ( TRUE)
clearly, not sufficient.
From stat2: ab 0; it seems expression missing it's relation sign!
well, if we consider <, > then obviously it's not sufficient!
but if we have ab = 0; to satisfy |a| > |b|, then a must be non-zero (but it can be < 0 or >0), so b should be 0!
e.g: a = -2, b = 0; 0 < -2 ( FALSE)
a = 2, b = 0; 0 < 2 ( TRUE)
Hence, it's not sufficient!
NOTE: if i consider, ab = 0 and a < 0 ; then the statement can be solved by using these both statements!
However, as 2nd statement isn't clear then i'll go for not sufficient. E!
Statement 2 : ab>= 0
There are several conditions like
i) a>0,b>0,ab>0
ii) a<0,b<0,ab>0
iii) a>0,b=0,ab=0
iv) a<0,b=0,ab=0
v) a=0,b<0,ab=0 ---> a*|b|=0 ---> a-b>0 ---> b>0 correct
v)a=0, b>0, ab=0 ---> a*|b|=0 ---> -b>0 which is wrongNo need to solve all the combinations above just the last two combinations have two different results so we can say its INSUFFICIENT.
Combining Statement 1) and 2) we get combinations
(ii)a<0,b<0,ab>0 ----> a*|b|<0 ---> a-b either positive or negative depending on values of "a" and "b" if a=-2,b=-3 then a-b> a*|b| correct...1>-6 ; if a=-3,b=-2 then a-b =-1, a*|b| = -3*2=-6 -1>-6 correct.
(iv)a<0,b=0,ab=0 ----> a=-3 ---> -3>0 wrong...
so from the two combinations we get different answers so its INSUFFICIENT...Ans:E
If anyone can explain this in a more simplistic way you are welcome. I tried my best
HELLO nARESH THIS IS A WONDERFUL POINT I HAVE NOT THOUGHT ABOUT THAT....a can't be zero as per |a| > |b|!...tHANK YOU....n@resh wrote:Answer will be still: E! nevertheless, a can't be zero as per |a| > |b|!nandy1984 wrote:Naresh has explained the statement 1...Coming to Statement 2 following the same procedureparul9 wrote:The second statement is ab >= 0. I will edit the main post too!n@resh wrote:From stat1: a < 0,parul9 wrote:If a and b are integers, and |a| > |b|, is a · |b| < a - b?
(1) a < 0
(2) ab 0
OA : [spoiler]E Can someone please explain??[/spoiler]
plug-in numbers: a = -1, b = 0 ; 0 < -1 ( FALSE)
a = -2, b = 1 ; -2 < -3 (FALSE)
a = -2, b = -1 ; -2 < -1 ( TRUE)
clearly, not sufficient.
From stat2: ab 0; it seems expression missing it's relation sign!
well, if we consider <, > then obviously it's not sufficient!
but if we have ab = 0; to satisfy |a| > |b|, then a must be non-zero (but it can be < 0 or >0), so b should be 0!
e.g: a = -2, b = 0; 0 < -2 ( FALSE)
a = 2, b = 0; 0 < 2 ( TRUE)
Hence, it's not sufficient!
NOTE: if i consider, ab = 0 and a < 0 ; then the statement can be solved by using these both statements!
However, as 2nd statement isn't clear then i'll go for not sufficient. E!
Statement 2 : ab>= 0
There are several conditions like
i) a>0,b>0,ab>0
ii) a<0,b<0,ab>0
iii) a>0,b=0,ab=0
iv) a<0,b=0,ab=0
v) a=0,b<0,ab=0 ---> a*|b|=0 ---> a-b>0 ---> b>0 correct
v)a=0, b>0, ab=0 ---> a*|b|=0 ---> -b>0 which is wrongNo need to solve all the combinations above just the last two combinations have two different results so we can say its INSUFFICIENT.
Combining Statement 1) and 2) we get combinations
(ii)a<0,b<0,ab>0 ----> a*|b|<0 ---> a-b either positive or negative depending on values of "a" and "b" if a=-2,b=-3 then a-b> a*|b| correct...1>-6 ; if a=-3,b=-2 then a-b =-1, a*|b| = -3*2=-6 -1>-6 correct.
(iv)a<0,b=0,ab=0 ----> a=-3 ---> -3>0 wrong...
so from the two combinations we get different answers so its INSUFFICIENT...Ans:E
If anyone can explain this in a more simplistic way you are welcome. I tried my best
HELLO nARESH THIS IS A WONDERFUL POINT I HAVE NOT THOUGHT ABOUT THAT....a can't be zero as per |a| > |b|!...tHANK YOU....n@resh wrote:Answer will be still: E! nevertheless, a can't be zero as per |a| > |b|!nandy1984 wrote:Naresh has explained the statement 1...Coming to Statement 2 following the same procedureparul9 wrote:The second statement is ab >= 0. I will edit the main post too!n@resh wrote:From stat1: a < 0,parul9 wrote:If a and b are integers, and |a| > |b|, is a · |b| < a - b?
(1) a < 0
(2) ab 0
OA : [spoiler]E Can someone please explain??[/spoiler]
plug-in numbers: a = -1, b = 0 ; 0 < -1 ( FALSE)
a = -2, b = 1 ; -2 < -3 (FALSE)
a = -2, b = -1 ; -2 < -1 ( TRUE)
clearly, not sufficient.
From stat2: ab 0; it seems expression missing it's relation sign!
well, if we consider <, > then obviously it's not sufficient!
but if we have ab = 0; to satisfy |a| > |b|, then a must be non-zero (but it can be < 0 or >0), so b should be 0!
e.g: a = -2, b = 0; 0 < -2 ( FALSE)
a = 2, b = 0; 0 < 2 ( TRUE)
Hence, it's not sufficient!
NOTE: if i consider, ab = 0 and a < 0 ; then the statement can be solved by using these both statements!
However, as 2nd statement isn't clear then i'll go for not sufficient. E!
Statement 2 : ab>= 0
There are several conditions like
i) a>0,b>0,ab>0
ii) a<0,b<0,ab>0
iii) a>0,b=0,ab=0
iv) a<0,b=0,ab=0
v) a=0,b<0,ab=0 ---> a*|b|=0 ---> a-b>0 ---> b>0 correct
v)a=0, b>0, ab=0 ---> a*|b|=0 ---> -b>0 which is wrongNo need to solve all the combinations above just the last two combinations have two different results so we can say its INSUFFICIENT.
Combining Statement 1) and 2) we get combinations
(ii)a<0,b<0,ab>0 ----> a*|b|<0 ---> a-b either positive or negative depending on values of "a" and "b" if a=-2,b=-3 then a-b> a*|b| correct...1>-6 ; if a=-3,b=-2 then a-b =-1, a*|b| = -3*2=-6 -1>-6 correct.
(iv)a<0,b=0,ab=0 ----> a=-3 ---> -3>0 wrong...
so from the two combinations we get different answers so its INSUFFICIENT...Ans:E
If anyone can explain this in a more simplistic way you are welcome. I tried my best
