cpay3245 wrote:On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amout of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.60 per glass on the first day, what was the price per glass on the second day?
On the 1st day, 1 unit of orange juice was mixed with 1 unit of water.
So, total amount of orangeade = (1 + 1) = 2 units
If each glass contained n units of orangeade, total number of glasses sold = 2/n
As price per glass was $0.60, total revenue on the 1st day = (0.60)*(2/n)
On the 1st day, 1 unit of orange juice was mixed with 2 units of water.
So, total amount of orangeade = (1 + 2) = 3 units
If each glass contained n units of orangeade, total number of glasses sold = 3/n
Total revenue on the 2nd day = Total revenue on the 1st day = (0.60)*(2/n)
Hence, price per glass on the 2nd day = (Total revenue)/(number of glasses sold) = (0.60)*(2/n)/(3/n) = (0.60)*(2/n)*(n/3) = (0.20)*2 = 0.40
The correct answer is D.
Note : Just put X = Y in the equation derived by srcc25anu as on the first day amount of orange juice is equal to amount of water.
