- bpolley00
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For a certain set of numbers, If x is in the set, then x-3 is also in the set. If the number 1 is in the set, which of the following must also be in the set?
I. 4
II. -1
III. -5
I only
II only
III only
I and II
II and III
Now I am sorry, but the answer explained by GMAC is sad, at best. Here is the logic: It is given that 1 is in the set. Therefore 1-3= -2 is in the set. Since we know -2 is in the set then -5 is also in the set. This set doesn't contain 4 or -1!. Therefore it is not true 4 or -1 must be in the set.
This is the absolute worst question I have seen to date guys. I am sorry, but this is just ridiculous. How do you know that the number 1 is the x in the set? The question merely states that it is in the set. For example X=4. If 4-3 =1, Therefore 1 is also in this set.
Am I missing something here? Any experts want to attempt a go at this type of logic?
I. 4
II. -1
III. -5
I only
II only
III only
I and II
II and III
Now I am sorry, but the answer explained by GMAC is sad, at best. Here is the logic: It is given that 1 is in the set. Therefore 1-3= -2 is in the set. Since we know -2 is in the set then -5 is also in the set. This set doesn't contain 4 or -1!. Therefore it is not true 4 or -1 must be in the set.
This is the absolute worst question I have seen to date guys. I am sorry, but this is just ridiculous. How do you know that the number 1 is the x in the set? The question merely states that it is in the set. For example X=4. If 4-3 =1, Therefore 1 is also in this set.
Am I missing something here? Any experts want to attempt a go at this type of logic?













