SQRT(4) = 2
4THROOT(4) = (2^2)1/4 = SQRT(2) = 1.414
3.414 just with evaluating 2 roots Eliminate A,B
Now its either c,d or e
cuberoot(4) ~= 1.6 (started with 1.5 and then did 1.6-> by trial)
Therefore greater than 4
M Value
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Stuart@KaplanGMAT
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We can quickly estimate.
root4 is 2
cuberoot 4 is between 1 and 2
quardicroot 4 is between 1 and 2.
So, the final answer is > 2 + 1 + 1, i.e > 4.. choose (E).
As an aside, for all n>1 and x>1, the nth root of x>1. In other words, even the billiionth root of 4 is > 1.
root4 is 2
cuberoot 4 is between 1 and 2
quardicroot 4 is between 1 and 2.
So, the final answer is > 2 + 1 + 1, i.e > 4.. choose (E).
As an aside, for all n>1 and x>1, the nth root of x>1. In other words, even the billiionth root of 4 is > 1.
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vishubn
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I swear !! that was nice way to put it !!cramya wrote:Thanks Stuart!As an aside, for all n>1 and x>1, the nth root of x>1. In other words, even the billiionth root of 4 is > 1.
vishu
thanks stuart
KILL !! DIE !! or BEAT my FEAR !!! de@D END!!
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ronniecoleman
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square Root 4 = 2
quad root 4 = root 2 = 1.414
cube root 4 = 2^2/3 ( 2/3 > 1/2 ) hence > 1.414
so X > 2+ 1.414 + 1.414
X> 4.8
quad root 4 = root 2 = 1.414
cube root 4 = 2^2/3 ( 2/3 > 1/2 ) hence > 1.414
so X > 2+ 1.414 + 1.414
X> 4.8
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