BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

DS Questions on probability

Expert replies
by knight247 » Tue Jun 21, 2011 11:27 pm
Is the probability of Arif and Alex, both being present in class, less than 0.75?
(1)Probability of Alex being present in the class is 0.7.
(2)Probability of Arif being present in the class is 0.8.
(A)Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.
(B)Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.
(C)BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient.
(D)EACH statement ALONE is sufficient to answer the question asked.
(E)Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data are needed.
Join the discussion
Source: — Data Sufficiency |

by Ian Stewart » Wed Jun 22, 2011 12:30 am
If the probability that Alex is present is 0.7, then the probability Alex and someone else are both present can't be more than 0.7, so Statement 1 is sufficient. Statement 2 is not, since it may be that the probability is 1 that Alex is present (in which case the probability would be 0.8 both are present) or the probability might be 0 that Alex is present (in which case the probability is 0 that both are present), to look only at the two extreme scenarios. So the answer is A.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
Join the discussion

by Geva@EconomistGMAT » Wed Jun 22, 2011 12:36 am
knight247 wrote:Is the probability of Arif and Alex, both being present in class, less than 0.75?
(1)Probability of Alex being present in the class is 0.7.
(2)Probability of Arif being present in the class is 0.8.
(A)Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.
(B)Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.
(C)BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient.
(D)EACH statement ALONE is sufficient to answer the question asked.
(E)Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data are needed.
Unless I'm missing something material, the answer seems to be a straightforward C.

P(alex and Arif) = p(Alex) * P (Arif), so you need both to find the probability and see whether it is less than 0.75.
Geva
Senior Instructor
Master GMAT
1-888-780-GMAT
https://www.mastergmat.com
Join the discussion

by Ian Stewart » Wed Jun 22, 2011 12:56 am
Geva@MasterGMAT wrote:
Unless I'm missing something material, the answer seems to be a straightforward C.

P(alex and Arif) = p(Alex) * P (Arif), so you need both to find the probability and see whether it is less than 0.75.
First, if P(Alex) is 0.7, then P(Alex)*P(Arif) is less than or equal to 0.7, since P(Arif) is at most 1. So we don't need both statements here.

Second, it's not at all clear that our events are independent, so it is not clear that we can even multiply our probabilities here. Maybe Arif and Alex are best friends, and when Arif cuts class, it's more likely Alex will cut class. Or perhaps they hate each other, so when Arif attends class, Alex is more likely to skip class. The way the information in the question is presented, you can only really generate inequalities here.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
Join the discussion

by Geva@EconomistGMAT » Wed Jun 22, 2011 1:01 am
Ian Stewart wrote:
Geva@MasterGMAT wrote:
Unless I'm missing something material, the answer seems to be a straightforward C.

P(alex and Arif) = p(Alex) * P (Arif), so you need both to find the probability and see whether it is less than 0.75.
First, if P(Alex) is 0.7, then P(Alex)*P(Arif) is less than or equal to 0.7, since P(Arif) is at most 1. So we don't need both statements here.

Second, it's not at all clear that our events are independent, so it is not clear that we can even multiply our probabilities here. Maybe Arif and Alex are best friends, and when Arif cuts class, it's more likely Alex will cut class. Or perhaps they hate each other, so when Arif attends class, Alex is more likely to skip class. The way the information in the question is presented, you can only really generate inequalities here.
Good catch on the first point.

I was considering the second point as a possible trap, but decided to ignore it - I've never actually any official question test the concept of dependent probabilities - they all eliminate this facet of the material. Technically, this question allows dependent probabilities (or at least does not explicitly rule them out), but that only indicates that this is not an official question.
Geva
Senior Instructor
Master GMAT
1-888-780-GMAT
https://www.mastergmat.com
Join the discussion

by mirantdon » Tue Jun 28, 2011 1:39 am
Consider the worst case scenario for option A
ie when arif has prob =1
--> p(arif and alex) = P(alex) *p(arif)
-->0.7*1 =0.7

Hence can be answered by only A
Join the discussion

by amit2k9 » Tue Jun 28, 2011 11:41 pm
yupp A it is.
For Understanding Sustainability,Green Businesses and Social Entrepreneurship visit -https://aamthoughts.blocked/
(Featured Best Green Site Worldwide-https://bloggers.com/green/popular/page2)
Join the discussion