AIM GMAT wrote:A group of 8 students take up a full row at a movie theater. There are 2 couples and the
2 people within each couple must sit together. In how many di& erent arrangements can
the students sit?
let c1 represents couple 1, and c2 represents couple 2, and the remaining four students be represented as s1,s2,s3,s4. Also let people within c1 and c2 be p1,p2,p3,p4 respectively.
as two persons within each couple must sit together therefore people within c1 and c2 will be consider as 1, so therefore we have total of 6 objects. these six objects can arrange themselves in 6! ways.
c1[(p1,p2)],c2[(p3,p4)],s1,s2,s3,s4 {it is one of the way of arrangement.}
now p1,p2 can interchange their position within a group in 2! ways similarly for p3 and p4 we have 2! ways.
so total no. of ways of arrangements would be 6!*2!*2!=2880
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