gmat_winter wrote:The price of a certain computer is discounted by 20% every year. After 3 years have passed the price of the computer will have been discounted by what fraction of the original price?
A)9/25
B)61/125
C)64/125
D)3/5
E)16/25
OAB
Let the original price = 1000.
1st year price = 1000 - 20% of 1000 = 1000-200 = 800.
2nd year price = 800 - 20% of 800 = 800-160 = 640.
3rd year price = 640 - 20% of 640 = 640-128 = 512.
Total discount = 1000-512 = 488.
Resulting fraction:
(discount)/(original) = 488/1000 = 61/125.
The correct answer is
B.
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