(1) If x = 1/2 = 0.5, then tenths digit of x = 5alex.gellatly wrote:In the decimal representation of x, where 0,x,1, what is the tenths digit if x is nonzero?
1. 16x is an integer
2. 8x is an integer
OA is B, but I got E... could someone please explain? Thanks
I don't understand. How can you get B if you clearly have two different numbers for the tenth digit of x. You say x=1/2 (.5) or x=1/8 (.125). So in your two examples the tenths digit could be either 5 or 1. Shouldn't this be insufficient?Anurag@Gurome wrote:(1) If x = 1/2 = 0.5, then tenths digit of x = 5alex.gellatly wrote:In the decimal representation of x, where 0,x,1, what is the tenths digit if x is nonzero?
1. 16x is an integer
2. 8x is an integer
OA is B, but I got E... could someone please explain? Thanks
If x = 1/16 = 0.0625, then tenths digit of x = 0
So, the tenths digit of x may or may not be zero. No unique answer.
So, (1) is NOT SUFFICIENT.
(2) If x = 1/2 = 0.5, then tenths digit of x = 5, which is non-zero.
If x = 1/8 = 0.125, then tenths digit of x = 1, which is non-zero. This implies that all numbers in the tenth place between 0 < x < 1 will always have a non-zero integer.
So, (2) is SUFFICIENT.
The correct answer is B.
There is a typo in the question, correct question is: In the decimal representation of x, where 0 < x < 1, is the tenths digit of x nonzero?alex.gellatly wrote: I don't understand. How can you get B if you clearly have two different numbers for the tenth digit of x. You say x=1/2 (.5) or x=1/8 (.125). So in your two examples the tenths digit could be either 5 or 1. Shouldn't this be insufficient?
