-
priyank.hirani
- Newbie | Next Rank: 10 Posts
- Posts: 5
- Joined: Wed Apr 11, 2012 9:19 am
Well, |x + y| >= 0, always.
But, if x + y = 0 (e.g. x = 1.5, y=-1.5), then it is not the case that:
|x + y| > 0
so A is false. B and D are false because |x + y| does not have to be greater than one, as we just determined.
In fact, 0 <= lx+yl < 4, but that is not among the answers here
C is true, since there is any x or y values that satisfy 0 <= lx+yl < 4 will also satisfy C.
