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In a survey problem

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by yvonne12 » Thu Apr 12, 2007 11:12 am
In a survey of 248 people, 156 are married, 70 are self emplyed and 25 percetn of those who are married are self employed. If a person is to randomly selected from those surveyed, what is the probability that the person selected will be self employed but not married?

1/8
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by gmatme » Thu Apr 12, 2007 1:55 pm
Married = 156
Self employed = 70

Married and self employed = (25% of 156) = 39

Self employed and not married = 70 - 39 =31

Probability = F/T = 31/248 = 1/8
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Re: In a survey problem

by ajith » Thu Apr 12, 2007 8:41 pm
yvonne12 wrote:In a survey of 248 people, 156 are married, 70 are self emplyed and 25 percetn of those who are married are self employed. If a person is to randomly selected from those surveyed, what is the probability that the person selected will be self employed but not married?

1/8
There is a Venn Diagram Approach to solve these kind of problems which is more visual and thus easier to understand.

Please refer the attachment :)
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