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Source: — Problem Solving |
Junior | Next Rank: 30 Posts
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by keeyu2 » Tue Mar 10, 2009 5:26 pm
L is the diameter of Circle S = L is Length of Square
Circle S Area = pi * (L/2)^2 = pi*(L^2)/4

D is the diameter of Circle T = D is Diagonal of a Square
D^2 = L^2 + L^2
D = Sqrt(L^2 + L^2)

Circle T Area = pi * (Sqrt(L^2 + L^2)/2)^2 = pi(L^2 + L^2)/4) =
pi*(2L^2)/4

Circle T is 2 times more than Circle S.
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