BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

the bus begins its route

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 am
Location: India
Thanked: 267 times
Followed by:80 members
GMAT Score:760

the bus begins its route

by sanju09 » Thu Mar 03, 2011 5:24 am
The number of passengers on a certain bus at any given time is given by the equation P = -2 (S - 4)^2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
(A) 32
(B) 30
(C) 24
(D) 14
(E) 0
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Source: — Problem Solving |
Legendary Member
Posts: 1337
Joined: Sat Dec 27, 2008 6:29 pm
Thanked: 127 times
Followed by:10 members

by Night reader » Thu Mar 03, 2011 5:50 am
P is zero when S=0; P is maximized at S=4 --> -2 (4 - 4)^2 + 32= 32 :)
two stops after P was maximized makes S=6 --> P = -2 (6 - 4)^2 + 32= 24

IOM C
sanju09 wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2 (S - 4)^2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
(A) 32
(B) 30
(C) 24
(D) 14
(E) 0
My knowledge frontiers came to evolve the GMATPill's methods - the credited study means to boost the Verbal competence. I really like their videos, especially for RC, CR and SC. You do check their study methods at https://www.gmatpill.com
Top
Legendary Member
Posts: 586
Joined: Tue Jan 19, 2010 4:38 am
Thanked: 31 times
Followed by:5 members
GMAT Score:730

by rohu27 » Thu Mar 03, 2011 5:52 am
the exp P = -2 (S - 4)^2 + 32, has greatest value only whenthe negative part is = 0,
so P shud be 32. 32=-2 (S - 4)^2 + 32, on sloving, S=4
so 2 stops after having greatest number means no. of pasengers at S=6.
at S=6, P=24.

[spoiler]ans: C[/spoiler]
sanju09 wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2 (S - 4)^2
+ 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
(A) 32
(B) 30
(C) 24
(D) 14
(E) 0
Top

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pm
Location: Milpitas, CA
Thanked: 1854 times
Followed by:523 members
GMAT Score:770

by Anurag@Gurome » Thu Mar 03, 2011 5:53 am
sanju09 wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2 (S - 4)^2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
(A) 32
(B) 30
(C) 24
(D) 14
(E) 0
As P = -2(S - 4)² + 32, the maximum value of P, i.e. number of passengers is 32, when S = 4.

Hence, at the after making 4 stops since beginning its route, the bus will have maximum number of passengers. Therefore, number of passengers after making 2 more stops, i.e. a total of 6 stops, the number of passengers in the bus = -2(6 - 4)² + 32 = 32 - 8 = 24

The correct answer is C.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Post new topic Post Reply
• Page 1 of 1