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Non Terminating Numbers

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Non Terminating Numbers

by satyavegi » Fri Jun 01, 2012 10:30 am
Q)A=0.abcabcabc.....and B=0.pqpqpq.......
Both of this are non terminating numbers,wherein a,b,c,p,q are integers between 1 to 9 ,not necessarliy distinct.
Then which of the following is and integer

A)1989*(A+B)
B)98901*(A+B)
C)989001*(A+B)
d)1000*(A+B)
e)999*(A+B)

OA -B
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by eagleeye » Fri Jun 01, 2012 5:42 pm
Hi satyavegi:

We have

A=0.abcabc.....
1000A=abc.abcabc......
1000A-A = 999A = abc

and

B=0.pqpq.....
100B=pq.pqpq........
100B-B= 99B = pq

so for the right option, we can multiply A and B with 99*999 = 98901. Hence B

Let me know if this helps :)
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