swerve wrote:How many widgets are contained in 2 crates and 2 boxes, if crate contain p boxes, each box contain c containers and each container contains 200 widgets?

$$A.\ 400pc^2+400pc$$
$$B.\ 400pc^2$$
$$C.\ 800pc$$
$$D.\ 800pc^2$$
$$E.\ 400pc+400c$$
The OA is E.

Please, can anyone explain this PS question? I tried to solve it but I can't get the correct answer. I need help. Thanks.

We have 2 crates and 2 boxes

2 crates + 2 boxes = 2 * (p boxes) + 2 * (c containers) = 2 * (p * (c containers)) + 2 * (c containers) = (2pc + 2c) containers = (2pc + 2c) * (200 widgets) = 400pc + 400c widgets

The correct answer: E

Hope this helps!

-Jay
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swerve wrote:How many widgets are contained in 2 crates and 2 boxes, if crate contain p boxes, each box contain c containers and each container contains 200 widgets?

$$A.\ 400pc^2+400pc$$
$$B.\ 400pc^2$$
$$C.\ 800pc$$
$$D.\ 800pc^2$$
$$E.\ 400pc+400c$$
The OA is E.

Since a crate contains p boxes and each box contains c containers and each container contains 200 widgets, there are (p)(c)(200) widgets per crate. Similarly, there are (c)(200) widgets per box.

So, the number of widgets in 2 crates is 2(p)(c)(200) = 400pc widgets, and the number of widgets in 2 boxes is 2(c)(200) = 400c widgets.

Thus, the total number of widgets in 2 crates and 2 boxes is 400pc + 400c.

Answer: E