If x and y are non-zero integers and |x| + |y| = 32, what is xy?
(1) -4x - 12y = 0
(2) |x| - |y| = 16
[spoiler]OA : A[/spoiler]
(1) -4x - 12y = 0
(2) |x| - |y| = 16
[spoiler]OA : A[/spoiler]
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Statement 1: -4x - 12y = 0.buoyant wrote:If x and y are non-zero integers and |x| + |y| = 32, what is xy?
(1) -4x - 12y = 0
(2) |x| - |y| = 16
Hi Mitch,If x and y are non-zero integers and |x| + |y| = 32, what is xy?
(1) -4x - 12y = 0
(2) |x| - |y| = 16
Statement 1: -4x - 12y = 0.
-4x = 12y
x = -3y.
Substituting x= -3y into |x| + |y| = 32, we get:
|-3y| + |y| = 32
3|y| + |y| = 32
4|y| = 32
|y| = 8
y = 8 or y = -8.
Your approach is perfect, but you neglected to answer the question stem, which asks not for the value of x but for the value of xy.buoyant wrote: i put the values of y back into the absolute value equation |x| + |y| = 32
instead of into the equation x=-3y
This gave me values of x = 24 or -24
So, i chose this statement as insufficient.
What was wrong with my approach?
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