If xy ≠0, what is the value of 1/x + 1/y?
(1) 1 / (x+y) = -1
(2) xy = 6(x+y)
[spoiler]B
Why why why?? I dont get it~!
(1) 1 / (x+y) = -1
(2) xy = 6(x+y)
[spoiler]B
Why why why?? I dont get it~!
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This is a great example of the utility of rewording the target question before examining the statements.gmatisgay wrote:If xy ≠0, what is the value of 1/x + 1/y?
(1) 1 / (x+y) = -1
(2) xy = 6(x+y)
If we arrange your calculations vertically, you'll see the slight error:EddieU wrote:Hi Brent, your calculations make totally sense. Can you please help me find my mistake in my thoughts?
what if we did not do anything with the question first? How come (1) is insufficient?
we have 1/x + 1/y=?
and they gave us the information 1/(x+y)= -1. if we multiply both sides with (x+y) we get 1 = -x-y if we add x to both sides we get x = -y. if we now substitute x with -y for the equation above, we get 1/-y + 1/y which is equal to -1/y + 1/y and this is equal to 0.
Where is the mistake?
Thanks in advance
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