Each of the following equations has at least one solution EXCEPT:
-2^n = (-2)^-n
2^-n = (-2)^n
2^n = (-2)^-n
(-2)^n = -2^n
(-2)^-n = -2^-n
-2^n = (-2)^-n
2^-n = (-2)^n
2^n = (-2)^-n
(-2)^n = -2^n
(-2)^-n = -2^-n
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put n=0jube wrote:Each of the following equations has at least one solution EXCEPT:
-2^n = (-2)^-n
2^-n = (-2)^n
2^n = (-2)^-n
(-2)^n = -2^n
(-2)^-n = -2^-n
Yes.. you got it rightjube wrote:Awesome! OA is indeed A.
I was getting confused between -2^n & (-2)^n -- couldn't understand the difference.
So if I'm getting this right, -x^n will always be - (x^n) i.e. we won't consider the - sign when calculating while (-x)^n will be a figure where the - sign *will* be considered when using the exponent.
Am I right?
Thanks!
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