Hey this is a direct one.
4^11-> can be rewritten as 2^22.
so the equation now turns out to be 5^21 * 2^22
What are the factors of 10? 2 and 5. it means to get one 10 we need a combination of one 2 and one 5.
how many such tens can be obtained from the equation? 21- tens.
the other extra two lies without pair.
therefore, n= 21.
Hope this helps!
Value of n
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fibbonnaci
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Just 2 is out from (5^21)* (2^22) such that (5^21)* (2^21) = 10^n, needless to say, n = [spoiler]hush...[/spoiler]adorendra wrote:(5^21)* (4^11) = 2* 10^n
What is the value of n?
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Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
