A
x<0, and (x^2)<(1/100), thus x<-(1/10), reciprocal of this is -10
x<-10
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n number
Source: Beat The GMAT — Problem Solving |
If n denotes a number to the left of 0 on the number line such that the square of n is less than 1/100, then the reciprocal of n must be
A). less than -10
B). Between -1 and -1/10
C). Between -1/10 and 0
D). Between 0 and 1/10
E). Greater than 10
If n = -1/11 then this squared would be 1/121 which would meet our condition. The reciprocal of -1/11 is -11 or greater than -10.
A.
A). less than -10
B). Between -1 and -1/10
C). Between -1/10 and 0
D). Between 0 and 1/10
E). Greater than 10
If n = -1/11 then this squared would be 1/121 which would meet our condition. The reciprocal of -1/11 is -11 or greater than -10.
A.
square of n <1/100
-1/10<n<+1/10 and n is left of 0 implies
-1/10 <n<0
reciprocate it
-10>1/n>1/0
1/n is always less than -10
Answer A
-1/10<n<+1/10 and n is left of 0 implies
-1/10 <n<0
reciprocate it
-10>1/n>1/0
1/n is always less than -10
Answer A
x<-1/10 is wrong it has to be x>-1/10.bstalling wrote:A
x<0, and (x^2)<(1/100), thus x<-(1/10), reciprocal of this is -10
x<-10
x^2 < (1/100) ==> -1/10<x
==> -10 >1/x
==> 1/x<-10
Thanks
raama
