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mariofelixpasku
- Senior | Next Rank: 100 Posts
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If x≠0, is |x| < 1?
(1) x^2 < 1
(2) |x| < 1/x
Answer is: D
can we derive some formula for the first case cause it would equal x^2 - 1 < 0
hence (x-1)(x+1)<0
how do we come up with a solution?
thanks in advance
(1) x^2 < 1
(2) |x| < 1/x
Answer is: D
can we derive some formula for the first case cause it would equal x^2 - 1 < 0
hence (x-1)(x+1)<0
how do we come up with a solution?
thanks in advance
