A perfect square is a squared number i.e a number which can be expressed as a product of two equal integers
$$i.e.4=>2\cdot2=2^2$$
So, 4 is a perfect square
Therefore, to find if a number is a perfect square we just have to find the square root and check if it gives a whole number without remainder
$$i.e.\sqrt{4}=2\ and\ 2^2=4$$
$$For\ 1266=>\sqrt{1266}=35.58\ \left(wrong\right)$$
$$For\ 1444=>\sqrt{1444}=38\ \left(correct\right)$$
$$For\ 2022=>\sqrt{2022}=44.97\ \left(wrong\right)$$
$$For\ 4034=>\sqrt{4034}=63.51\ \left(wrong\right)$$
$$For\ 8122=>\sqrt{8122}=90.12\ \left(wrong\right)$$

1444 is the only perfect square.
Answer = option B

BTGmoderatorDC wrote:Which of the following numbers is a perfect square?

A. 1266
B. 1444
C. 2022
D. 4034
E. 8122

OA B

Source: Veritas Prep

Let's begin by eliminating answer choices C and E since a perfect square cannot end in 2,3,7 or 8.

Now between A, B and D. Well, we can see that all numbers are even for starters. This means that they also must be divisible by 4.

Only B fits the bill.

Therefore, __B__ is the correct answer.