mv<pv<0
i.e. mv is negative
either m or v is negative
pv is also negative, hence either p or v is negative.
question: v>0 or is v positive?
St 1 m<p
mv<pv<0 only if m and p are negative
(you can prove this by plugging numbers where both m and p are negative and one where only v is negative)
SUFF
St 2 m<0 hence m and p both are negative so v has to be positive
SUFF
Answer is D
Hope the solution is clear
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
ds-gmatprep
Source: Beat The GMAT — Data Sufficiency |
we have three inequalities disguised here
mv<pv or (m-p)v<0
mv<0 and pv<0
from 1 m-p<0 hence in (m-p)v<0; v>0 suff
from 2 m<0 hence in mv<0; v>0 suff
hence D
mv<pv or (m-p)v<0
mv<0 and pv<0
from 1 m-p<0 hence in (m-p)v<0; v>0 suff
from 2 m<0 hence in mv<0; v>0 suff
hence D
















