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Problem Solving — algebra and arithmetic (GMAT Focus Edition)
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by Rockying** » Sun Sep 04, 2011 5:27 am
85 are married, 80 have cars, 75 have phones, and 70 have houses. How many minimum persons are married, have phone, car and houses on a scale of 100.
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by cans » Mon Sep 05, 2011 4:17 am
10.. correct?
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by VivianKerr » Thu Sep 29, 2011 7:08 am
For these, it helps to think of the number that DOESN'T fit into each category.

75 are married so 25 are not. 85 have phones, so 15 do not.

20 do not have cars, and 30 don't have houses.

So the excluded number from each category is 25, 15, 30, and 20.

Since we want the minimum that doesn't fit into ANY category, we will pretend there is not overlap: 100-(25+15+30+20) = 10
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