[1 – {1/ (x + 1)}]/x for all values of x

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Which of the following is equivalent to [1 - {1/ (x + 1)}]/x for all values of x for which both expressions are defined?
(A) 1
(B) x + 1
(C) 1/x
(D) 1/ (x + 1)
(E) x^2 + x


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by selango » Tue Sep 14, 2010 5:58 am
[1 - {1/ (x + 1)}]/x

=[x/x+1]/x

=1/x+1

Pick D
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by klmehta03 » Tue Sep 14, 2010 11:01 am
agree the ans is D

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by Brian@VeritasPrep » Tue Sep 14, 2010 12:09 pm
Hey guys,

Nice work on choice D! A few strategic thoughts on this one:


1) They don't give you an equation, but rather an expression and ask you what it equals. This means that your job isn't to solve for a variable, but rather to simplify the expression. Simplicity is your goal - and when you're using algebra you should always have a goal in mind so that the steps you take have a direction.

2) One easy way to simplify an expression like this is to reduce the number of terms. Here you have two terms in the numerator (1 and 1/(x+1) and one in the denominator. To simplify the numerator, you can find a common denominator for the two subtracted terms:

1 - 1/(x+1)
(x+1) / (x+1) - 1/(x+1) ---> Use x+1 as your common denominator
x / (x+1) ----> subtract the two terms


Now you have:

[x/(x+1)] / x

At this point, all of your terms are multiplication/division, so you can simplify by taking the denominator and multiplying it as a reciprocal:

x/(x+1) * 1/x

The x term in the numerator of the first and the denominator of the second will cancel, leaving:

1/(x+1)

Which is answer choice D.


The keys here are to:

1) Recognize that it's not an equation, but rather an expression that needs to be simplified

2) Take steps to simplify by:

-Reducing the number of terms
-Eliminating denominators

Quite often this test will rely on your ability to use algebra for a goal - either to solve for a variable or simplify an expression. When you see that in play, have a goal in mind and take algebraic steps to get there.
Brian Galvin
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Chief Academic Officer
Veritas Prep

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