BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Combination problem - please help!

Expert replies
by abbyyip » Sat May 12, 2007 7:20 pm
Can someone please explain the concept of indistinguishable items within a combination problem, such as the one below:

Ben needs to form committee of 3 from a group of 8 engineers. If 2 of the engineers are too inexperienced to serve in the same committee, how many different committees can Ben form?
- 20
- 30
- 50
- 56
- 336

I think the answer is 50, but I have no idea how that was derived. Thanks!

PS. This question can be found in the Princeton Review - Manual for the GMAT ver. 8.2 p. 346

Thanks! :D
Join the discussion
Source: — Problem Solving |

by Cybermusings » Sat May 12, 2007 11:28 pm
Free selections (without any limitations ) = 8C3 = 56 ways
Selections in which the 2 engineers are always together = 2C2 * 6C1 = 6 ways
Thus selections in which the 2 inexperienced people are never together = 56-6 = 50 ways
Join the discussion