(n-x)+(n-y)+(n-z)+(n-K)=?
stmt1,
(x+y+z+k)/4=n
x+y+z+k=4n
The expression can be rephrased as,
4n-(x+y+z+k)=4n-4n=0
Suff
stmt2,
x=a,y=a+1,z=a+2,k=a+3
-->4n-(4a+6)
We dont know value of n and a.
Insuff
Pick A
What is the value of the expression below.......
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