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Source: — Problem Solving |
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by tohellandback » Mon Aug 17, 2009 10:10 pm
xy+z=x(y+z)
xY+z=xy+xz
z=xz
z(x-1)=0
x =1, or z=0

answer E
The powers of two are bloody impolite!!
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by GambitOS » Thu Aug 20, 2009 10:47 am
May be A?

xy+z=x(y+z)

x=0; z=0; y=any integer.

0*1+0=0*(1+0)

0=0

So A?
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by DanaJ » Thu Aug 20, 2009 12:17 pm
Actually, I think tohellandback's approach is the correct one. You are looking for something that MUST BE TRUE, which is exactly what he provided: an algebraic demonstration.

Your approach is in the COULD BE TRUE section and it is not opposed to his findings: in your example z = 0, which is a part of "x = 1 or z = 0" statement. You could also try it with other numbers: x = 24 and z = 0, for instance.
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by cmr209 » Tue Aug 25, 2009 7:59 pm
Answer from GMAT prep

E) x=1 or z=0
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