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sk8ternite
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x^n = (x^n+2) for any integer n. Is it true that x>0?
(1) x = (x^2)-2
(2) 2x < x^5
For x^n = (x^n+2) to satisfy,
x can be either -1,0,1
Statement I:
It satisfies only when x = -1
So it is sufficient to say that x>0 is false.
Statement II:
It satisfies only when x = -1
So it is sufficient to say that x>0 is false.
So the answer is D.
Please update the actual answer.
