BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Question 1 (nov. 25)

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 245
Joined: Thu Aug 16, 2007 12:41 pm
by bacali » Tue Nov 25, 2008 7:50 am
Q3:
If a committee of 3 people is to be selected from among 5 married couples so that the committee does not include two people who are married to each other, how many such committees are possible?


A. 20
B. 40
C. 50
D. 80
E. 120


OA: D
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 683
Joined: Tue Jul 22, 2008 1:58 pmFollowed by: 2 members
Location: Dubai
Thanked: 73 times

by mals24 » Tue Nov 25, 2008 8:18 am
You have 5 couples and you want to select 3 people and no 2 people ot of the 3 are married.

We have 10 ways to select the first person.
We have 8 ways to select the 2nd person
We have 6 ways to select the 3rd person.

Since we are just selecting people, ABC is the same as BCA.

Hence to avoid over counting we divide by 3!

Total ways = 10*6*8/3! = 480/3! = 80.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 245
Joined: Thu Aug 16, 2007 12:41 pm

by bacali » Tue Nov 25, 2008 8:38 am
mals24 wrote:You have 5 couples and you want to select 3 people and no 2 people ot of the 3 are married.

We have 10 ways to select the first person.
We have 8 ways to select the 2nd person
We have 6 ways to select the 3rd person.

Since we are just selecting people, ABC is the same as BCA.

Hence to avoid over counting we divide by 3!

Total ways = 10*6*8/3! = 480/3! = 80.
I was getting the 10*6*8 right but wasn't diving by 3!. Thanks a lot!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1