winniethepooh wrote:Sir, I really appreciate your responses.
But, I didn't understand this explanation!
Can it be any clearer?
Also, the Values for x can be 1 and 2 or is it that the Inequalities 1 and 2 are possible?
Yes, the values of x can be 1 and 2 and then some of the quantities will be equal. And that is the key point of the solution.
For example, when x = 1, 1/x = x².
Hence, we can expect that on two sides of 1, the ordering of 1/x and x² will be different. In fact, for x < 1, x² < 1/x and for x > 1, 1/x < x².
Similarly, when x = 2, 2x = x²
Hence, we can expect that on two sides of 2, the ordering of 2x and x² will be different. In fact, for x < 2, x² < 2x and for x > 2, 2x < x².
Similarly, when x = 1/√2, 1/x = 2x
Hence, we can expect that on two sides of 1/√2, the ordering of 2x and 1/x will be different. In fact, for x < 1√2, 2x < 1/x and for x > 1/√2, 1/x < 2x
Now, we have to combine these results to determine the combined ordering.
At each of these three values two of the three quantities will have same value. But the options do not have any equalities. Hence, we don't have to consider them. But they are possible and they are the key point to determine the ordering.
