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Source: — Problem Solving |
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by sam2304 » Fri Apr 13, 2012 11:09 pm
Best way is to plug in numbers

1. x > y > z => x = 10, y = 2, z = 1
x > y^2 > z^4 => 10 > 4 > 1
True

2. z > y > x => x = 1/10, y = 1/5, z = 1/3
x > y^2 > z^4 => 1/10 > 1/25 > 1/81
True

3. x > z > y => x = 100, z = 1/3, y = 1/5
x > y^2 > z^4 = 100 > 1/25 > 1/81
True

Basically we need to check fractions and -ve values whenever sign is not given. 1 and 2 can be easily proved. 1 is true for all positive integers and 2 is the reversal which applies for all fractions in this case and negative nos won't come in this as we have even powers. 3rd case we have to check it independently.

IMO E.
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by killer1387 » Fri Apr 13, 2012 11:31 pm
WITH E
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