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shankyrams
- Newbie | Next Rank: 10 Posts
- Posts: 7
- Joined: Wed Apr 30, 2008 12:40 am
Please refer attachment.
I thought both statements together solve the problem.
My solution flow is as below -
1) t1 = (d1/r1) ; t2= (d2/r2)
2) From solution option 1 d1= d2+30
3) From solution option 1 r2= r2+30
4) From (2) and (3) t1 = (d2+30)/(r2+30)
5) Is t1 > t2 => {(d2+30)/(r2+30)} > (d2/r2)
Subtracting 1 from both sides we get
{(d2-r2)/(r2+30)} > (d2-r2)/(r2)
Left side denominator greater than right side by 30. Hence t1 is definately not greater that t2. SOLUTION ARRIVED.
I thought both statements together solve the problem.
My solution flow is as below -
1) t1 = (d1/r1) ; t2= (d2/r2)
2) From solution option 1 d1= d2+30
3) From solution option 1 r2= r2+30
4) From (2) and (3) t1 = (d2+30)/(r2+30)
5) Is t1 > t2 => {(d2+30)/(r2+30)} > (d2/r2)
Subtracting 1 from both sides we get
{(d2-r2)/(r2+30)} > (d2-r2)/(r2)
Left side denominator greater than right side by 30. Hence t1 is definately not greater that t2. SOLUTION ARRIVED.
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