BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Gmat prep -acme truck sales

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Community Manager
Posts: 1049
Joined: Sun Apr 06, 2008 5:15 pmFollowed by: 27 members
Location: Pittsburgh, PA
Thanked: 113 times
GMAT Score:710

by dmateer25 » Tue Nov 18, 2008 12:44 pm
I am going to eliminate zeros from this to make it easier.

Ed…..680
Ann…450
Bob…360
Dot…210
Cal…190

You know the median is going to be the middle number because there are 5 people.

We know Cal’s sales are still less than Ann’s sales after they fix the error

We know the median after fixing the error is 330

The only way for the median to be 330 is if Ann or Bob have 330 total sales.

Bob at 330:
It would take 140 from Ann’s to make Cal’s 330. However, this would leave ann with 310 which would be less than Cal’s. Therefore, this is not possible.

Ann at 330:
It would take 120 away from Ann. Ann would have 330 and Cal would have 310.
This satisfies the criteria of the problem.

The answer would be 120. Hope this helps!
Last edited by dmateer25 on Tue Nov 18, 2008 12:55 pm, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 51
Joined: Fri Sep 05, 2008 11:06 am
Thanked: 1 times

by GG04 » Tue Nov 18, 2008 12:52 pm
Thx Dmateer25. Since I got this question from some document, I have no way or verifying the correct answer.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 683
Joined: Tue Jul 22, 2008 1:58 pmFollowed by: 2 members
Location: Dubai
Thanked: 73 times

by mals24 » Tue Nov 18, 2008 12:55 pm
arranging the sales in increasing order

C- 190
D - 310
B - 360
A - 450
E - 680

Median - 360

Median changes to 330.

Only C and As sales figure change rest all remain same. Also A>C

This means either C is the new median or A

C can't be the new median since then C>A
Hence A is the new median, its value = 330
Change - 450 - 330. = 120.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Tue Nov 18, 2008 3:24 pm
One more vote for D)

It has to be 120 or 140 so that the median is 330(odd count of numbers) i.e 190+140 or 450-120

Since its given Cal's sale even after taking this misrecorded sale from his total is greater than Bob's it has to be 120 subtracted from 450 making the median 330

Cal - 330
Bob - 310
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1