OG-11 DS#150

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OG-11 DS#150

by haidgmat » Thu Aug 05, 2010 6:15 pm
Can someone please explain this to me?

Henry purchased 3 items during a sale. He received a 20% discount off the regular price of the most expensive item and a 10% discount off the regular price of each of the other 2 items. Was the total amount of the 3 discounts greater than 15% of the sum of the regular prices of the 3 items?

1. The regular price of the most expensive item was $50, and the regular price of the next most expensive item was $20

2. The regular price of the least expensive item was $15

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by Rahul@gurome » Thu Aug 05, 2010 6:51 pm
Solution:
(1) alone is obviously not sufficient because we know the regular price of only 2 items and not the third.
Similarly even (2) alone is not sufficient because only the regular price of 1 item is given.

Next combine both the statements together and check.

On combining we have that regular price of most expensive item is $50.
Discount on this item is 20% of $50 which is $10.
Regular price of second most expensive is $20 and discount on this is 10% of 20 which is $2.
Regular price of third most expensive $15 and discount on this is 10% of 15 which is $1.5.

Sum of all the discounts is 10+2+1.5 = $13.5.
Sum of the regular price of all the three items is 50+20+15 = $85.
15% of $85 is $12.75.

Since 13.5% is greater than is 12.75%, we conclude that the total amount of the 3 discounts is greater than 15% of the sum of the regular prices of the 3 items.

The correct answer is (C).
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by Ian Stewart » Thu Aug 05, 2010 7:45 pm
haidgmat wrote:Can someone please explain this to me?

Henry purchased 3 items during a sale. He received a 20% discount off the regular price of the most expensive item and a 10% discount off the regular price of each of the other 2 items. Was the total amount of the 3 discounts greater than 15% of the sum of the regular prices of the 3 items?

1. The regular price of the most expensive item was $50, and the regular price of the next most expensive item was $20

2. The regular price of the least expensive item was $15

If you have a solution other than the one in the book that would GREAT!
The answer is A, not C. Conceptually, this is just a weighted average problem, though that fact is a bit disguised. The idea is this: suppose you buy two items, X and Y. On item X you get a 20% discount, and on item Y you get a 10% discount. Your overall discount is thus somewhere between 10% and 20%:

* if X and Y cost the same amount, your overall discount will be 15%
* If X costs more than Y, your overall discount will be closer to 20%
* If Y costs more than X, your overall discount will be closer to 10%

So here, think of the two cheaper items as a single purchase. From Statement 1, we know that the two cheaper items cost at most $40, so they cost less than the most expensive item, which cost $50. Thus our overall discount must be greater than 15%. Statement 2 is clearly insufficient, so the answer is A.

You can also prove all of this algebraically. From Statement 1 we know our expensive item costs $50. Say our two other items cost $x in total. Then our total discount, in dollars, is (0.2)(50) + 0.1x = 10 + 0.1x. To find our percent discount, we divide this by the total expenditure, which is 50+x (here I'll write each percentage as a decimal, so I won't multiply by 100, and we'll write 15% as 0.15). If we want to know for which values of x this overall discount will be greater than 15%, we can set up the following inequality:

(10 + 0.1x) / (50 + x) > 0.15
10 + 0.1x > 7.5 + 0.15x
2.5 > 0.05x
50 > x

So provided the two less expensive items cost less than $50 in total, the overall discount will be greater than 15%. Since Statement 1 guarantees that the two less expensive items cost less than $40, it is sufficient.

The concept in the question above is one you encounter more often in mixtures questions. If you combine, say, 50 Liters of a 20% salt solution with 50 Liters of a 10% salt solution, you'll get a solution which is exactly 15% salt. If you combine 50 Liters of the 20% solution with, say, 40 Liters (or any other amount less than 50 Liters) of the 10% solution, the resulting concentration will be greater than 15%.
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by clock60 » Fri Aug 06, 2010 1:37 pm
also think that the answr is A
to the problem
let it be prices of the items x1.x2.x3 thus x1<=x2<x3, ( as we are not given that two items can`t be equal in price)
and now is
0,2*x3+0,1*(x1+x2)>0,15(x1+x2+x3)
after little transforming
is x3>x1+x2-the main question
(1)x3=50 and x2=20 so x1 must be less that 20 let it be 19
50>20+19 so sufficient
(2) x1=15, but we are not given the value of other two so impossible to compare, rescind 2 st