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Question (nov. 25)

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Question (nov. 25)

by bacali » Tue Nov 25, 2008 8:01 am
If the average (arithmetic mean) of x, y, and 20 is 10 greater than the average of x, y, 20, and 30, what is the average of x and y?

A. 40
B. 45
C. 60
D. 75
E. 95


OA: E
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Re: Question (nov. 25)

by iamcste » Tue Nov 25, 2008 8:34 am
bacali wrote:If the average (arithmetic mean) of x, y, and 20 is 10 greater than the average of x, y, 20, and 30, what is the average of x and y?

A. 40
B. 45
C. 60
D. 75
E. 95


OA: E

(x+y+20/3)-[(x+y+20+30)/4 ]=10

Solve for x and y

x+y=190

Arihmentic mean of x and y=(x+y)/2=95

IMO E
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