BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

a ps from gmat club

Expert replies
Source: — Data Sufficiency |

by clock60 » Sun May 15, 2011 12:46 pm
hi
If \frac{x}{|x|}<x which of the following must be true about x?
is it possible to write underlined part in some other way.i guess no one knows exactly what is written here
Join the discussion

by Ian Stewart » Mon May 16, 2011 1:54 pm
diebeatsthegmat wrote:If \frac{x}{|x|}<x which of the following must be true about x?

(A) x>1

(B) x>-1

(C) |x|<1

(D) |x|=1

(E) |x|^2>1

a is my answer choice. whats yours>?
The notation in the question "\frac{x}{|x|}<x" is used in a mathematical typesetting environment called TeX - it's not something you'll ever see on the GMAT. The question should begin:

If x/|x| < x, which of the following...

Now x/|x| is either equal to 1 (if x is positive) or to -1 (if x is negative). So we can rephrase the inequality:

* if x > 0, then 1 < x
* if x < 0, then -1 < x

So there are two ranges of possible values for x; either x > 1, or -1 < x < 0.

From here you can see that the only answer which *must* be true is B, since if x is in either of the ranges above, x is certainly greater than -1. Most of the other answers (besides D) *could* be true, but are not always true.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
Join the discussion

by sourabh33 » Mon May 16, 2011 3:48 pm
Hi Ian

I have a small doubt regarding statements A & B.

I can't think of any value of x>1 that will not be true for the equation x/|x| < X
Versus For option B (x>-1), when x = 0, then the equation x/|x| < X may not be true

Please help.
Join the discussion

by Ian Stewart » Mon May 16, 2011 5:27 pm
sourabh33 wrote:Hi Ian

I have a small doubt regarding statements A & B.

I can't think of any value of x>1 that will not be true for the equation x/|x| < X
Versus For option B (x>-1), when x = 0, then the equation x/|x| < X may not be true

Please help.
I think you must be looking at the question backwards. We *know* that x/|x| is less than x. We want to know which answer choice *must* be true. It doesn't need to be true that x > 1, because x could be equal to -0.5, so A cannot be the right answer.

I think you're trying to answer the opposite question. That is, you're assuming that answer A is true, and you're trying to prove that x/|x| is less than x. It certainly is if x > 1, but that doesn't make A correct here, because that's not what the question is asking you to do.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
Join the discussion

by sourabh33 » Mon May 16, 2011 6:04 pm
Thank you so much for the clarification.
Ian Stewart wrote: * if x > 0, then 1 < x
* if x < 0, then -1 < x

So there are two ranges of possible values for x; either x > 1, or -1 < x < 0.
But, as you said in your post that two ranges possible for x are x>1 and -1<x<0, than x cannot be 0 because either x has to be greater than 1 or x has to be in between -1 and 0.

Now in statement x>-1

In Range -1<x<0 the given equation is true
In Range x=0 the given equation is not defined
In Range 0<x<1 the given equation x/|x| is not true (it is actually greater than x (0.5/0.5 > 0.5))
In Range x=1 the equation is not true
In Range 1<x the equation is true
Join the discussion