- talaangoshtari
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Let the a� = x and a₃ = y, where x and y are positive integers.talaangoshtari wrote:In a certain sequence, each term beyond the second term is equal to the average of the previous two terms. If a1 and a3 are positive integers, which of the following is NOT a possible value of a5
A.-9/4
B.0
C.9/4
D.75/8
E.41/2
Since a₃ = (1/2)(a� + a₂), we get:
y = (1/2)(x + aâ‚‚)
2y = x + aâ‚‚
aâ‚‚ = 2y - x.
Since a₄ = (1/2)(a₂ + a₃), we get:
aâ‚„ = (1/2)(2y - x + y) = (3y - x)/2.
Since a₅ = (1/2)(a₃ + a₄), we get:
aâ‚… = (1/2)[ y + (3y - x)/2 ]
= y/2 + (3y - x)/4
= (5y - x)/4
= (10y - 2x)/8
= (even integer - even integer)/8
= (even integer)/8.
Since aâ‚… = (even integer)/8, it is not possible that aâ‚… = 75/8.
The correct answer is D.

















