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For integers a and b, 16a = 32^b. Which of the following correctly expresses a in terms of b?
A. a = 2^b
B. a = 4^b
C. a = 2^(5b − 4)
D. a = 4^(5b − 4)
E. a = 2^(5b)
OA C
Source: Veritas Prep
A. a = 2^b
B. a = 4^b
C. a = 2^(5b − 4)
D. a = 4^(5b − 4)
E. a = 2^(5b)
OA C
Source: Veritas Prep
