An object thrown directly upward is at a height of h feet after t seconds, where h = -16(t-3)^2 + 150. At what height, in feet, is the object 2seconds after it reaches its maximuh height?
a)6
b)86
c)134
d)150
e)166
The solution goest on to explain that the minimum value of (t-3)^2 occurs when t = 3 and also the maximum value. I Can see that the minimum value would be at t= 3 as 3-3 =0 but not sure how the maximum also occurs at t= 3?
a)6
b)86
c)134
d)150
e)166
The solution goest on to explain that the minimum value of (t-3)^2 occurs when t = 3 and also the maximum value. I Can see that the minimum value would be at t= 3 as 3-3 =0 but not sure how the maximum also occurs at t= 3?
