BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Word problem questions (deck of cards etc)

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 25
Joined: Sat Jun 25, 2011 8:49 am
by oex85 » Sat Jul 09, 2011 9:09 am
Did the first of the GMAT prep tests today and had some problems from the start with two word problems.

1. For a finite sequence of nonzero numbers, the number of variatinos in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6?

Alternatives: One, two, three, four or five.

Just can't wrap my head around this text. Don't want to give my faulty answer just yet...


2. In a certain deck of cards, each card has a positive integer written on it. In a multiplication game, a child draws a card and multiplies the integer on the card by the next larger integer. If each possible product is between 15 and 200, then the least and greatest integers on the cards could be:

- 3 and 15
- 3 and 20
- 4 and 13
- 4 and 14
- 5 and 14


Looks like I'm gonna have to work on my word problems. Appreciate any help with these Q:s!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Quantitative Reasoning |
Junior | Next Rank: 30 Posts
Posts: 20
Joined: Sat Sep 13, 2008 11:30 am

by sgarnepudi » Sat Jul 09, 2011 9:39 am
Q1: Ans is 3.

Q2: Ans is 4 and 13.

Frankenstein is correct.
Last edited by sgarnepudi on Sat Jul 09, 2011 9:51 am, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1448
Joined: Tue May 17, 2011 9:55 amFollowed by: 53 members
Location: India
Thanked: 375 times

by Frankenstein » Sat Jul 09, 2011 9:44 am
Hi,
Q1 is nothing but asking for sign changes. A sign change is + to -, and - to +
Consider 1,-3,2,5,-4,-6. sign changes from 1 to -3, -3 to 2 and 5 to -4
So, answer is three

Q2)Product of a number and next larger number means if you pick a number n, the product is n*(n+1)
Go from options,
if we pick 3, n(n+1) is 12 not in the range (15,200)
So, A,B are out
if n = 4, n(n+1) = 20 ..fine in the range (15,200)
if n = 13, n(n+1) = 182 ..fine in the range (15,200)
if n= 14, n(n+1) = 14*15 = 210 outside the range (15,200)

Hence, C
Cheers!

Things are not what they appear to be... nor are they otherwise
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 25
Joined: Sat Jun 25, 2011 8:49 am

by oex85 » Sat Jul 09, 2011 5:26 pm
Frankenstein wrote:Hi,
Q1 is nothing but asking for sign changes. A sign change is + to -, and - to +
Consider 1,-3,2,5,-4,-6. sign changes from 1 to -3, -3 to 2 and 5 to -4
So, answer is three

Q2)Product of a number and next larger number means if you pick a number n, the product is n*(n+1)
Go from options,
if we pick 3, n(n+1) is 12 not in the range (15,200)
So, A,B are out
if n = 4, n(n+1) = 20 ..fine in the range (15,200)
if n = 13, n(n+1) = 182 ..fine in the range (15,200)
if n= 14, n(n+1) = 14*15 = 210 outside the range (15,200)

Hence, C
Thank you! Great answer. I really need to get better translating text into equations... However, this piece of text just confuses me so much:

"the number of variatinos in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative"

Guess I should ignore this part and just read:

"What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6? "

Need some practice with the word problems.

Thanks again.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 461
Joined: Tue May 10, 2011 9:09 amFollowed by: 3 members
Location: pune
Thanked: 36 times

by amit2k9 » Mon Jul 18, 2011 10:51 pm
a (1,-3); (-3,2) ; (5,-4) hence 3.

b 15 < n(n+1) < 200
means,

n * (n+1) = 4*5 = 20
and 13*14 = 182.

4-13.
For Understanding Sustainability,Green Businesses and Social Entrepreneurship visit -https://aamthoughts.blocked/
(Featured Best Green Site Worldwide-https://bloggers.com/green/popular/page2)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1