- harsh.champ
- Legendary Member
- Posts: 1132
- Joined: Mon Jul 20, 2009 3:38 am
- Location: India
- Thanked: 64 times
- Followed by:6 members
- GMAT Score:760
The number of non-negative real roots of 2^x - x - 1 = 0 equals
(A)0
(B)1
(C)2
(D)3
(E)4
The OA is C.
For reference,here is the soln.[spoiler]
2^x - x - 1 = 0
2^x - 1 = x
If we put x = 0, then this is satisfied and we put x = 1, then this is also satisfied.
Now we put x = 2, then this is not valid.[/spoiler]
(A)0
(B)1
(C)2
(D)3
(E)4
The OA is C.
For reference,here is the soln.[spoiler]
2^x - x - 1 = 0
2^x - 1 = x
If we put x = 0, then this is satisfied and we put x = 1, then this is also satisfied.
Now we put x = 2, then this is not valid.[/spoiler]
Last edited by harsh.champ on Tue Feb 09, 2010 4:28 am, edited 1 time in total.
It takes time and effort to explain, so if my comment helped you please press Thanks button 
Just because something is hard doesn't mean you shouldn't try,it means you should just try harder.
"Keep Walking" - Johnny Walker
Just because something is hard doesn't mean you shouldn't try,it means you should just try harder.
"Keep Walking" - Johnny Walker

















