Here is the explanation-
since y is +ve, x must be +ve(1) 3x = 2y
y =x + 1/2*x
=> y = x + a positive number
=> y > x hence sufficient
x= 3, y=2 also satisfies this thus not sufficient(2) x + y = 5
Hence [spoiler][A][/spoiler]
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If y > 0, is y greater than x ?
Source: Beat The GMAT — Data Sufficiency |
IMO [spoiler][A][/spoiler]
Here is the explanation-
y =x + 1/2*x
=> y = x + a positive number
=> y > x hence sufficient
Hence [spoiler][A][/spoiler]
Here is the explanation-
y =x + 1/2*x
=> y = x + a positive number
=> y > x hence sufficient
Hence [spoiler][A][/spoiler]
If you feel like it, hit thanks 
Let's solve this using Co-ordinate Geometry.
Since y > 0, we're concerned with only the Ist and the IInd quadrants.
Statement (1) is a straight line y = 3x/2
For the given line y is always greater than x. You can see this by comparing it with the line y = x.
SUFFICIENT.
Statement (2): Draw a line with x and y intercepts = 5
If we compare it with y = x again, we notice that a certain portion of this line is below y = x (made bold in figure) and a certain portion (made dotted in figure) is above it.
So, for the given statement y can be greater than x or smaller than it.
INSUFFICIENT.
[spoiler](A)[/spoiler] is the answer.
See another problem solved easily by Co-ordinate Geometry:
https://www.beatthegmat.com/if-b-1-and-2 ... tml#469327
Since y > 0, we're concerned with only the Ist and the IInd quadrants.
Statement (1) is a straight line y = 3x/2
For the given line y is always greater than x. You can see this by comparing it with the line y = x.
SUFFICIENT.
Statement (2): Draw a line with x and y intercepts = 5
If we compare it with y = x again, we notice that a certain portion of this line is below y = x (made bold in figure) and a certain portion (made dotted in figure) is above it.
So, for the given statement y can be greater than x or smaller than it.
INSUFFICIENT.
[spoiler](A)[/spoiler] is the answer.
See another problem solved easily by Co-ordinate Geometry:
https://www.beatthegmat.com/if-b-1-and-2 ... tml#469327
Aneesh Bangia
GMAT Math Coach
[email protected]
GMATPad:
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GMAT Math Coach
[email protected]
GMATPad:
Facebook Page: https://www.facebook.com/GMATPad
