BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

ds - x^2 x^3 question

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
User avatar
Legendary Member
Posts: 965
Joined: Thu Jan 28, 2010 12:52 amFollowed by: 34 members
Thanked: 156 times
GMAT Score:720

by vineeshp » Tue Apr 05, 2011 6:44 pm
OA is C?

1) x = 2, x^2 = 2x. The only values at which x^2 = 2x are x=2, and also x=0. N.S as this only proves x >= 0.

2) x = , x^3 = 3x. The only values at which x^3 = 3x are x= sqrt(3), x = - sqrt(3), and also x=0. X can be zero, positive or negative.

1 and 2) Only overlap is at 0 to solve the combined inequalities. Hence C
Vineesh,
Just telling you what I know and think. I am not the expert. :)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 436
Joined: Tue Feb 08, 2011 3:07 amFollowed by: 6 members
Thanked: 72 times

by manpsingh87 » Tue Apr 05, 2011 8:19 pm
ccassel wrote:Hi,

How would you explain the answer to this question?

Is it true that x>0?

(1) x^2=2x
(2) x^3=3x

cheers,
1) x^2=2x;
x^2-2x=0;
x(x-2)=0; hence x can be either 0,2; therefore 1 alone is not sufficient to answer the question.

2) x^3-3x=0;
x(x^2-3)=0; hence x can be either 0,sqrt(3),-sqrt(3) therefore 2 alone is not sufficient to answer the question.

combining 1 and 2 we have;
x^3-x^2-x=0;
x(x^2-x-1)=0; x=0 or x^2-x-1=0 as also by combining 1 and 2 we have different solutions possible, therefore answer should be E..!!
O Excellence... my search for you is on... you can be far.. but not beyond my reach!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Tue Apr 05, 2011 8:52 pm
manpsingh87 wrote:
ccassel wrote:Hi,

How would you explain the answer to this question?

Is it true that x>0?

(1) x^2=2x
(2) x^3=3x

cheers,
1) x^2=2x;
x^2-2x=0;
x(x-2)=0; hence x can be either 0,2; therefore 1 alone is not sufficient to answer the question.

2) x^3-3x=0;
x(x^2-3)=0; hence x can be either 0,sqrt(3),-sqrt(3) therefore 2 alone is not sufficient to answer the question.

combining 1 and 2 we have;
x^3-x^2-x=0;
x(x^2-x-1)=0; x=0 or x^2-x-1=0 as also by combining 1 and 2 we have different solutions possible, therefore answer should be E..!!
That is not the correct way of combining both the statements.
Obviously each statement alone is not sufficient, because they are each giving more than 1 value, which may or may not be more than 0.
Combine both the statements together and check.
Take the first equation.
You get that x^2 = 2x.
Or, x(x - 2) = 0.
So, x is either 0 or 2.
Next, take the second equation.
So, x^3 - 3x = 0.
Or, x(x^2 - 3) = 0.
This gives that x = 0, sqrt3 or -sqrt3.
When we combine, we have to look for values which satisfy both the equations simultaneously.
Only 0 does that and so, x = 0.
Or x is not greater than 0.

The correct answer is therefore (C).
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 436
Joined: Tue Feb 08, 2011 3:07 amFollowed by: 6 members
Thanked: 72 times

by manpsingh87 » Tue Apr 05, 2011 9:00 pm
Anurag@Gurome wrote:
manpsingh87 wrote:
ccassel wrote:Hi,

How would you explain the answer to this question?

Is it true that x>0?

(1) x^2=2x
(2) x^3=3x

cheers,
1) x^2=2x;
x^2-2x=0;
x(x-2)=0; hence x can be either 0,2; therefore 1 alone is not sufficient to answer the question.

2) x^3-3x=0;
x(x^2-3)=0; hence x can be either 0,sqrt(3),-sqrt(3) therefore 2 alone is not sufficient to answer the question.

combining 1 and 2 we have;
x^3-x^2-x=0;
x(x^2-x-1)=0; x=0 or x^2-x-1=0 as also by combining 1 and 2 we have different solutions possible, therefore answer should be E..!!
That is not the correct way of combining both the statements.
Obviously each statement alone is not sufficient, because they are each giving more than 1 value, which may or may not be more than 0.
Combine both the statements together and check.
Take the first equation.
You get that x^2 = 2x.
Or, x(x - 2) = 0.
So, x is either 0 or 2.
Next, take the second equation.
So, x^3 - 3x = 0.
Or, x(x^2 - 3) = 0.
This gives that x = 0, sqrt3 or -sqrt3.
When we combine, we have to look for values which satisfy both the equations simultaneously.
Only 0 does that and so, x = 0.
Or x is not greater than 0.

The correct answer is therefore (C).
agreed sir, actually i forgot to check whether the values obtained by solving x^2-x-1 are satisfying 1 and 2 or not...!!! and i believe sir we can combine that way as well...!!! because i have found this method to be very handy in some particular questions...!!!
anyways thanks a lot sir for pointing my error..!!!
O Excellence... my search for you is on... you can be far.. but not beyond my reach!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Tue Apr 05, 2011 9:25 pm
manpsingh87 wrote:
agreed sir, actually i forgot to check whether the values obtained by solving x^2-x-1 are satisfying 1 and 2 or not...!!! and i believe sir we can combine that way as well...!!! because i have found this method to be very handy in some particular questions...!!!
anyways thanks a lot sir for pointing my error..!!!
Thanks. You are welcome!
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1