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Combination/Permutation

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by jessicamuniz » Wed Dec 03, 2008 4:46 am
Hi there, here is simple one, but can somebody explain it to me please. I am still trying to understand the combination / permutation problems.

How many ways can 3 different coins be placed in 2 different bags?





Ans 8
Thanks in advance
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Source: — Problem Solving |

by xyzabc123 » Wed Dec 03, 2008 6:13 am
let the coins be a nickel, a dime and a quarter.
if none of them is placed in the 1st bag and the rest in the second, we get 1 combinations.
if one of them is placed in the 1st bag and the rest in the second, we get 3 combinations.
if two of them are placed in the 1st bag and the rest in the second, we get 3 combinations.
if all three of them are placed in the 1st bag and nothing in the second, we get 1 combinations.

Sum them all up and you get 8.
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