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set 39 #14

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set 39 #14

by KL08 » Mon Sep 24, 2007 12:28 pm
14. If the perimeter of square region S and the perimeter of circular region C are equal, then the ratio of the area of S to the area of C is closest to
(A) 3/2
(B) 4/3
(C) 3/4
(D) 2/3
(E) 1/2

OA is C
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by kajcha » Mon Sep 24, 2007 12:46 pm
Let R be radius of circle ans S be side of square

2*pi*R = 4S => R=4S/2pi

Area of Sq = S^2 ----(1)

Area of Circle = pi*(R^2) => pi*16*S^2/(4*Pi*pi) ----(2)

Divide (1)/ by (2)

It comes to pi/4. pi=3.14 almost equal to 3

so ans is 3/4
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