I solved it differently. Consider the portion; with A & B. Clearly B is the median that cut the rectangular board in two halves. if we name the rectangle WXBZ (W being top right corner and then proceed clockwise).
So, ZB = 5 feet.
Now draw the diagonal, WB. This will intersect the line Aa (which makes a angle of 45 degree on ZB), at center which will be the center of the reactangular board also. Let name this point, O.
Now draw a perpendicular from O to ZB, that will intersect the ZB at (say) 'p'. Now Ap = 3 inches (as triangle AOP is isoceles with OP as 3 inches).
As O is the center point, perpendicular drawn from O to ZB will cut it in two halves again, thus; Zp = pB = 5 feet.
And hence, AB = Ap + pB =
5 ft 3 inches.
This solution might be looking lengthy, but it took me 40 sec to solve the question.
Sorry, I'm not providing the diagram (thats y I had to explain all this

)
regards
niks...