sandipgumtya wrote:Hi Mitch,
I didn't get how r u getting angle CBD=CDB=60DEG.Can u pl explain once more?
Angles inside a triangle must sum to 180.
Since statement 1 indicates that ∠BCD=60, and the angles inside ∆BCD must sum to 180, ∠CBD + ∠CDB = 120.
The prompt indicates that ABCD is a rhombus.
In a rhombus, all sides are EQUAL.
Thus, CB=CD.
If two sides of a triangle are equal, the opposite angles are also equal.
In ∆BCD, since CB=CD, ∠CBD = ∠CDB.
Since ∠CBD = ∠CDB, and ∠CBD + ∠CDB = 120, ∠CBD = ∠CDB = 60.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at
[email protected].
Student Review #1
Student Review #2
Student Review #3