Joshua and Jose work at an auto repair center with 4 other workers. For a survey on healthcare insurance, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that Joshua and Jose will boh be chosen.
a) 1/15
b) 1/12
c) 1/9
d) 1/6
e) 1/3
I have looked at other explanations which is very simple P(first person) x P (second person) = 2/6 x 1/5 = 1/15, which is the correct answer.
Combinatorics is the weakest part of my prep, and now probability, which im generally good at, is suffering because I've starting confusing combinatorics and simple probability questions.
How do we know that this question should be attempted with simple probability, vs combinatorics, which is what I tried to use and obviously got wrong.
The way i figured was total way that 6 different people can be chosen = 6!
Ways to chose 2 people from 6 = 6!/2!4! = 15
Total probability = 15/6!
Of course looking at the answers makes me realizing my method is not even making sense, but how do i attempt this question using combinatorics? Is it simply 1/# of ways to chose 2 people from 6 which is 15 thus 1/15?
a) 1/15
b) 1/12
c) 1/9
d) 1/6
e) 1/3
I have looked at other explanations which is very simple P(first person) x P (second person) = 2/6 x 1/5 = 1/15, which is the correct answer.
Combinatorics is the weakest part of my prep, and now probability, which im generally good at, is suffering because I've starting confusing combinatorics and simple probability questions.
How do we know that this question should be attempted with simple probability, vs combinatorics, which is what I tried to use and obviously got wrong.
The way i figured was total way that 6 different people can be chosen = 6!
Ways to chose 2 people from 6 = 6!/2!4! = 15
Total probability = 15/6!
Of course looking at the answers makes me realizing my method is not even making sense, but how do i attempt this question using combinatorics? Is it simply 1/# of ways to chose 2 people from 6 which is 15 thus 1/15?
